解方程组：（x-y\2）-1=2x+y\2与（3x+y\3）+2=x-y\3.

1.(x-y)/2-2/2=(2x+y)/2x-y-2=2x+yx-2x-y-y=2-x-2y=22.(3x+y)/3+6/3=(x-y)/33x+y+6=x-y3x-x+y+y=-62x+2y=-6x+y=-3综合1.2.由1.变形得x=-2-2y带入2.得-2-2y+y=-3y=1所以x=-3-1=-4即x=-4 y=1