因为此数列除以8的余数的规律是:1,1,2,3,5,0,5,5,2,7,1,0,1,1,2,3,…它的循环周期是:1,1,2,3,5,0,5,5,2,7,1,0;
2000÷12=166…8,
在循环数中第8个数对应的是5,
因此第2000项除以8的余数是5;
答:此数列的第2000项除以8的余数是5.
一列数1,1,2,3,5,8,13,21…从第三项开始每一项是前两项的和,此数列的第2000项除以8的余数是多少?
一列数1,1,2,3,5,8,13,21…从第三项开始每一项是前两项的和,此数列的第2000项除以8的余数是多少?
数学人气:654 ℃时间:2019-12-13 17:58:11
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