(2/3a)-[2/(a+b)]{[(a+b)/3a]-a-b}÷[(a-b)/b]

数学人气：916 ℃时间：2020-07-17 16:31:43

优质解答

[2/3a - 2/(a+b) * (a+b/3a - a - b)] / (a-b)/a
=[2/3a-2/(a+b)*(a+b)*(1/3a-1)]/(a-b)/a
=a[2/3a-2(1/3a-1)]/(a-b)
=a*2/(a-b)
=2a/(a-b)

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