已知：cos(x-pai/4)=根号2/10,x属于pai/2,3pai/4,求sin(2x+pai/3)的值

cos(2(x-pai/4))=2 (cos(x-pai/4))^2-1=2×(√2/10)^2-1=-24/25cos(2(x-/4)) = cos(2x-pai/2)=sin2xsin2x=-24/25x(pai/2,3pai/4)则2x（pai,3pai/2）cos2x=-√(1-sin^2(2x))=-7/25sin(2x+pai/3)=sin2xcos pai...