求方程y''+y'=sinx+3的通解
求方程y''+y'=sinx+3的通解
数学人气：889 ℃时间：2020-02-03 23:18:29
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∵齐次方程y''+y'=0的特征方程是r^2+r=0,则r1=-1,r2=0∴此齐次方程的通解是y=C1e^(-x)+C2 (C1,C2是常数)∵设原方程的解为y=Ax+Bcosx+Csinx,则代入原方程化简得A+(-B+C)cosx+(-B-C)sinx=sinx+3==>A=3,-B+C=0,-B-C=1==...
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