∵y-1与x+3成正比例
∴设y-1=k(x+3)
∵x=0时,y=10
∴10-1=k(0+3)
9=3k
k=3
∴y-1=3(x-3)
∴y=3x+10
若y-1与x+3成正比例,且x=0时,y=10,则y与x之间的函数关系式为
若y-1与x+3成正比例,且x=0时,y=10,则y与x之间的函数关系式为
数学人气：468 ℃时间：2020-02-03 14:46:16
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