2n-(4n^2-kn+3)^0.5的极限是1,则k的值等于?
2n-(4n^2-kn+3)^0.5的极限是1,则k的值等于?
数学人气:380 ℃时间:2020-05-25 17:33:15
优质解答
2n-根号(4n^2-kn+3)=根号(4n^2)-根号(4n^2-kn+3)=4n^2-(4n^2-kn+3)--------------------------------= (上下同时乘以根号(4n^2)+根号(4n^2+kn+3))根号(4n^2)+根号(4n^2-kn+3)kn-3--------------------------------...
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