等比数列{an}中,Sn表示前n项和,a3=3S2+1,a4=2S3+1,则公比q为

a3=3S2+1,a3-3S2=1,a4=2S3+1a4-2S3=1a3-3S2=a4-2S3a3=a4-2S3+3S2a3=a4-2S3+2S2+s2a3=a4-2(S3-S2)+s2a3=a4-2a3+s23a3=a4+s24a3=a4+s2+a34a3=s44a1q^2=a1(1-q^4)/(1-q)4q^2=(1-q^4)/(1-q)4q^2=(1+q^2)(1+q)(1-q)/(1-q)...