证明:
设AD/BD=AE/EC=k,
则AD=kBD,AE=kEC,
则AB=AD+BD=(k+1)BD,AC=AE+EC=(k+1)EC,
∴EC/AC=1/(k+1),BD/AB=1/(k+1),
∴EC/AC=BD/AB
得证
如图,△ABC中,DE//BC,AD/BD=AE/EC,求证EC/AC=BD/AB
如图,△ABC中,DE//BC,AD/BD=AE/EC,求证EC/AC=BD/AB
数学人气:312 ℃时间:2019-08-17 02:55:59
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