an=2(an-1+2^n)-2^n
→(an+2^n)/(an-1+2^n)=2
→{an+2^n}是首项为3,q=2的等比数列
→an+2^n=3*2^(n-1)
→an=3*2^(n-1)-2^n
已知数列{An}满足a1=1,且An=2An-1+2^n(n大于等于2且n属于整数).求数列的通项公式?
已知数列{An}满足a1=1,且An=2An-1+2^n(n大于等于2且n属于整数).求数列的通项公式?
数学人气:324 ℃时间:2019-09-29 03:06:37
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