40/40=1mol
稀释的溶液的溶质的物质的量浓度=1/4=0.25mol/L可以写下公式吗?不写不懂啊?物质的量=质量/摩尔质量=40/40=1mol
溶质的物质的量浓度=溶质的物质的量/溶液的体积=1/4=0.25mol/L
将40 克NAOH固体溶与水配制成2升溶液,若将此溶液稀释到4升,求稀释的溶液的溶质的物质的量浓度
将40 克NAOH固体溶与水配制成2升溶液,若将此溶液稀释到4升,求稀释的溶液的溶质的物质的量浓度
化学人气:275 ℃时间:2020-02-05 04:17:41
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