若m为正整数,则【1-（-1）＾n+1】（n＾2-1）/2的值是奇数还是偶数

奇数
当n为奇数时：n+1为偶数,（-1）＾n+1=1,1-（-1）＾n+1=0,【1-（-1）＾n+1】（n＾2-1）/2=0
当n为偶数时：n+1为奇数,（-1）＾n+1=-1,1-（-1）＾n+1=2,n＾2为偶数
n＾2-1为奇数,【1-（-1）＾n+1】（n＾2-1）/2就变成2（n＾2-1）/2=n＾2-1所以是奇数.