已知:|x-1/x+1|+(3y+1/2y+3)²=0,求代数式2/(3x-1)-3/(3y+2)的值.

(1)
|x-1/x+1|+(3y+1/2y+3)²=0
非负式=0
∴(x-1)/(x+1)=0
x-1=0
x=1
(3y+1)/(2y+3)=0
∴3y+1=0
y=-1/3
2/(3x-1)-3/(3y+2)
=2/2-3/(-1+2)
=1-3
=-2
(2)
x²+y²-4x-6x+13=0
(x-2)²+(y-3)²=0
非负式=0
∴x-2=0
x=2
y-3=0
y=3
(-y/x³)²÷(-1/xy)×(x/y²)²
=y²/x^6×(-xy)×x²/y^4
=-1/(x³y)
=-1/(8×3)
=-1/24
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