9 |
4 |
25 |
4 |
3 |
2 |
25 |
4 |
定义域为〔0,m〕
那么在x=0时函数值最大
即y最大=(0-
3 |
2 |
25 |
4 |
9 |
4 |
25 |
4 |
又值域为〔-
25 |
4 |
即当x=m时,函数最小且y最小=-
25 |
4 |
即-
25 |
4 |
3 |
2 |
25 |
4 |
0≤(m-
3 |
2 |
9 |
4 |
即m≥
3 |
2 |
即(m-
3 |
2 |
9 |
4 |
m-
3 |
2 |
3 |
2 |
3 |
2 |
3 |
2 |
0≤m≤3 (2)
所以:
3 |
2 |
故选C.
25 |
4 |
25 |
4 |
3 |
2 |
3 |
2 |
9 |
4 |
25 |
4 |
3 |
2 |
25 |
4 |
3 |
2 |
25 |
4 |
9 |
4 |
25 |
4 |
25 |
4 |
25 |
4 |
25 |
4 |
3 |
2 |
25 |
4 |
3 |
2 |
9 |
4 |
3 |
2 |
3 |
2 |
9 |
4 |
3 |
2 |
3 |
2 |
3 |
2 |
3 |
2 |
3 |
2 |