解下列方程 (1.)3x+4=0 (2.) 7y+6=-6y (3.)5x+2=7x+8 (4.)3y-2=y+1+6y
解下列方程 (1.)3x+4=0 (2.) 7y+6=-6y (3.)5x+2=7x+8 (4.)3y-2=y+1+6y
亲 iiiiiii than you
亲 iiiiiii than you
其他人气:269 ℃时间:2020-02-04 01:14:23
优质解答
13x=-4x=-4/327y+6y=-613y=-6y=-6/1337x-5x=2-82x=-6x=-343y-2=y+1+6y4y=-3y=-3/4
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