在三角形ABC 求证：sinA/(sinB+sinC)+sinB/(sinA+sinC)+sinC（sinA+sinB）

证明：设sinA/a=sinB/b=sinC/c=k,则sinA=ak,sinB=bk,sinC=ck,sinA/(sinB+sinC)+sinB/(sinA+sinC)+sinC（sinA+sinB）=a/(b+c)+b/(a+c)+c/(a+b）=[a(a+c)(a+b)+b(b+c)(a+b)+c(b+c)(a+c)]/[(a+b)(b+c)(a+c)]=[aaa+bbb+c...