O是三角形ABC内一点,且OB、OC分别平分角ABC和角ACB.（1）若角A等于46度,求角BOC

∵∠A＝46
∴∠ABC+∠ACB＝180-∠A＝134
∵BD平分∠ABC
∴∠ABD＝∠ABC/2
∴∠BEC＝∠A+∠ABD＝∠A+∠ABC/2
∵CD平分∠ACB
∴∠ACD＝∠ACB/2
∴∠BOC＝∠BEC+∠ACD
＝∠A+（∠ABC+∠ACB）/2
＝46+134/2
＝113°2、∵∠A＝n∴∠ABC+∠ACB＝180-∠A＝180-n∵BD平分∠ABC∴∠ABD＝∠ABC/2∴∠BEC＝∠A+∠ABD＝∠A+∠ABC/2∵CD平分∠ACB∴∠ACD＝∠ACB/2∴∠BOC＝∠BEC+∠ACD＝∠A+（∠ABC+∠ACB）/2＝n+(180-n)/2＝90°+n/23、∵∠BOC＝148∴90+n/2＝148∴n＝116°∴∠A＝116°角ABC／2的意思是不是二分之一角ABC是的哦、谢啦