-3y=x+2z(1)
(1)式两边同时平方,即::(-3y)^2=(x+2z)^2
9y^2=x^2+4xz+4z^2
x^2-9y^2+4z^2+4xz= - 9y^2+ (x^2+4z^2+4xz)
= - 9y^2+9y^2
=0
正确答案欢迎采纳!感谢了
已知-3y=x+2z,求x的平方-9y的平方+4z的平方+4xz
已知-3y=x+2z,求x的平方-9y的平方+4z的平方+4xz
数学人气:963 ℃时间:2020-02-02 22:52:59
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