简单:因为y=f(x)的定义域是0≤x≤2,所以,函数f(x+1)+f(2x-1)要有意义,只要
0≤x+1≤2,且
0≤2x-1≤2.
得出:1/2≤x≤1
函数相加的定义域怎么求?
函数相加的定义域怎么求?
如若y=f(x)的定义域是【0,2】,则函数f(x+1)+f(2x-1)的定义域是?
如若y=f(x)的定义域是【0,2】,则函数f(x+1)+f(2x-1)的定义域是?
数学人气:393 ℃时间:2020-02-03 16:07:01
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