已知函数f(x)=lnx - ax + (1-a)/x -1(a∈R) ,当0≤a

f(x)定义域为(0,+无穷)f'(x)=1/x- a - (1-a)/(x ^2) =-(ax^2-x+1-a)/(x^2)=-(ax-1+a)(x-1)/(x^2)(ax-1+a)(x-1)=0的二正为1,1/a-1(0≤a2,1/a-1>1)y=(ax-1+a)(x-1)是开口向上的抛物线,当00,为单调递增函数当x>1/a-1...