A=48乘以1/[3的平方-4]+1/[4的平方-4]+...+1/[100的平方-4]】与A最接近的正整数是

1/[(n+2)^2-4] = 1/[n(n+4)] = (1/4)[1/n - 1/(n+4)],A = 48[1/[3^2-4] + 1/[4^2-4]+1/[5^2-4]+1/[6^2-4]+1/[7^2-4]+...+1/[95^2-4]+1/[96^2-4]+1/[97^2-4]+1/[98^2-4]+1/[99^2-4]+1/[100^2-4]=48/4[1/1 - 1/5 + 1/2...