函数y+cosx+sinx的最大值等于?

y=(√2){[(√2)/2]sinx+[(√2)/2]cosx}=(√2)[sinxcos(π/4)+cosxsin(π/4)]=(√2)sin[x+(π/4)]
则当x+(π/4)=π/2+2kπ(k∈Z),即x=π/4+2kπ(k∈Z)时,y取最大值√2.