由|a-3|-3+a=0可得,
|a-3|=3-a,
根据绝对值的性质可知,
a-3≤0,a≤3.
故选A.
若|a-3|-3+a=0,则a的取值范围是( ) A.a≤3 B.a<3 C.a≥3 D.a>3
若|a-3|-3+a=0,则a的取值范围是( )
A. a≤3
B. a<3
C. a≥3
D. a>3
A. a≤3
B. a<3
C. a≥3
D. a>3
数学人气:839 ℃时间:2019-10-01 19:54:59
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