原式=[3(a+b)³-2(a+b)²-4(a+b)]÷(a+b)
=3(a+b)³÷(a+b)-2(a+b)²÷(a+b)-4(a+b)÷(a+b)
=3(a+b)²-2(a+b)-4
[3(a+b)的立方-2(a+b)的平方-4a-4b】÷(a+b)
[3(a+b)的立方-2(a+b)的平方-4a-4b】÷(a+b)
数学人气：621 ℃时间：2020-01-30 07:41:15
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