Fe2O3+3CO
| ||
160 112
5000t×76% x×98%
| 160 |
| 112 |
| 5000t×76% |
| 98%×x |
x≈2714.3t
答：日产含Fe98%的生铁2714.3t．
某钢铁厂每天需消耗5000t含Fe2O376%的赤铁矿石，该厂理论上可日产含Fe 98%的生铁多少吨？
某钢铁厂每天需消耗5000t含Fe2O376%的赤铁矿石，该厂理论上可日产含Fe 98%的生铁多少吨？
化学人气：889 ℃时间：2019-10-19 05:49:14
优质解答
设日产含Fe 98%的生铁的质量为x．
Fe2O3+3CO
2Fe+3CO2
160 112
5000t×76% x×98%
=
，
x≈2714.3t
答：日产含Fe98%的生铁2714.3t．
Fe2O3+3CO
160 112
5000t×76% x×98%
x≈2714.3t
答：日产含Fe98%的生铁2714.3t．
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