因为100000a+10000b+1000c+100a+10b+c
=100100a+10010b+1001c
=1001(100a+10b+c)
1001是四位数,比100a+10b+c大,
所以最大公约数一定是1001.
故答案为:1001.
所有形如 abcabc 的六位数中(其中a,b,c均为丛0到9的整数,a≠0)它们的最大公约数是_.
所有形如 abcabc 的六位数中(其中a,b,c均为丛0到9的整数,a≠0)它们的最大公约数是______.
数学人气:600 ℃时间:2019-08-22 15:19:36
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