y=f(x))在(2,f(2))处的切线为y=2x-1函数g(x)=x²+f(x)在(2,g(2))处切线方程

∵y=f(x))在(2,f(2))处的切线为y=2x-1=2(x-2)+3
∴f′(2)=2 f(2)=3
∵g′(x)=2x+f′(x)
∴g′(x)=4+2=6 g(2)=4+3=7
∴函数g(x)=x²+f(x)在(2,g(2))处切线方程:
y=6(x-2)+7=6x-5