已知x,y互为相反数,且x≠0,a,b互为倒数,|n|=2 求代数式x-n/ab-(-y)+y/x的值

x,y互为相反数,且x≠0,a,b互为倒数,|n|=2
x+y=0 ab=1 n1=2 n2=-2
x-n/ab-(-y)+y/x
=x+y-n/ab+y/x
=0-n-1
=-1-n
=-3或1
代数式x-n/ab-(-y)+y/x的值为-3或1