x/(x-1)=1+3/(x^2+x-2)
方程两边同时乘以x²+x-2,得
则x(x+2)=x²+x-2+3
则x²+2x=x²+x+1
则x=1
检验：将x=1代入原方程,分母=0,所以x=1是增根
所以原方程无解.
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