计算下列方阵的行列式：1 a b c a 0 0 0 b 0 0 0 c 0 0 0

说我答案错了那是绝对不可能的,除非你的题目写错了.以下是顶级行业软件MATLAB的计算结果,也是0.
1,a,b,c
a,0,0,0
b,0,0,0
c,0,0,0
r2-a*r1:
1,a,b,c
0,-a^2,-ab,-ac
b,0,0,0
c,0,0,0
r3-b*r1:
1,a,b,c
0,-a^2,-ab,-ac
0,-ab,-b^2,-bc
c,0,0,0
r4-c*r1:
1,a,b,c
0,-a^2,-ab,-ac
0,-ab,-b^2,-bc
0,-ac,-bc,-c^2
r3-(b/a)r2:
1,a,b,c
0,-a^2,-ab,-ac
0,0,0,0
0,-ac,-bc,-c^2
r4-(c/a)r2:
1,a,b,c
0,-a^2,-ab,-ac
0,0,0,0
0,0,0,0
=1*(-a^2)*0*0
=0