请用公式法计算x^2-(2m+1)x+1+m=0的两个根~

x^2-(2m+1)x+1+m=0用公式法计算:△=√{[-(2m+1)]^2-4*1*(1+m)}=√{4m^2+4m+1)-4-4m}=√(4m^2-3)x1={-[-(2m+1)]+√(4m^2-3)}÷2=0.5*(2m+1)+0.5*√(4m^2-3)x2=0.5*(2m+1)-0.5*√(4m^2-3)