y=sin2x-根号3cos2x
=2[sin2xcosπ/3-cos2xsinπ/3]
=2sin(2x-π/3)
x∈[π/6,π/2]
当x=5π/12；y有最大值=2
当x=π/6,y有最小值=0
函数值域为[0,2]
求三角函数值域 y=sin2x-根号3cos2x.x属于[派/6,派/2]
求三角函数值域 y=sin2x-根号3cos2x.x属于[派/6,派/2]
数学人气：604 ℃时间：2019-10-19 12:30:37
优质解答
我来回答
类似推荐
猜你喜欢
- 1如图,已知平行四边形abcd中.点e,f分别是边DC,AB的中点,AE,CF的对角线BD分别交于
- 2什么是马克思资本周转理论的意义?
- 3修路队要修一条长1km、宽6m的公路,铺30cm厚的三合土,至少需要三合土多少立方米?
- 4this is the second time that i have broke the cup,that 引导的什么从句?
- 5一圆与y轴相切圆心在直线x-3y=0上,在Y=X上截得的弦长为2倍根号7,求此圆方程
- 6解方程1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+7x+12)-1/x+1
- 7I am to love you really very much ,I do not dare say to you but ,can penitence,however your forg
- 8I’m going tell you about a friend of mine beat with the uglystick at birth求译
- 9More and more people think it necessary to let .为什么这里只用it,而不是it is necessary to .
- 10What has two legs but can't walk