设静水速度是x
4(x+3)=6(x-3)
4x+12=6x-18
x=15
答:距离是:4*(15+3)=72千米
一货轮从甲地顺流而下4小时到达乙地,原路返回需要6小时才能到达甲地,已知水流速度为3千米/小时,求甲、乙两地间的距离是多少千米?
一货轮从甲地顺流而下4小时到达乙地,原路返回需要6小时才能到达甲地,已知水流速度为3千米/小时,求甲、乙两地间的距离是多少千米?
数学人气：731 ℃时间：2019-10-23 06:10:57
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