y'=[ln(4x+5)^3]'
=1/(4x+5)^3×[(4x+5)^3]'
=1/(4x+5)^3×[3(4x+5)^2](4x+5)'
=1/(4x+5)^3×[3(4x+5)^2]×4
=1/(4x+5)^3×[12(4x+5)^2]
=[12(4x+5)^2]/(4x+5)^3谢谢了
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