dln y =sinxde^x+e^xdsinx
dy/y=sinxe%xdx+cosxe^xdx
dy/dx=ye^x(sinx+cosx)
ln y = e^x sinx 求dy/dx.
ln y = e^x sinx 求dy/dx.
教材的答案是[ye^ycosx]/[1-ye^ysinx]
教材的答案是[ye^ycosx]/[1-ye^ysinx]
数学人气:978 ℃时间:2020-03-30 12:19:40
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