已知抛物线y=x平方-2(a+1)x+2a平方-a的对称轴方程x=2

1、因为,y = x²-2(a+1)x+2a²-a 的对称轴方程为 x = -[-2(a+1)]/2 = a+1 ,所以,a+1 = 2 ,解得：a = 1 ；2、y = x²-2(a+1)x+2a²-a = x²-4x+1 ,当 y = 0 时,x²-4x+1 = 0 ,解得：x = 2±...