a(n+1)=2an/(an+2)
1/a(n+1)=(an+2)/2an=1/2+1/an
1/a(n+1)-1/an=1/2
则{1/an}为等差数列,首项为1,增量为1/2
所以,1/an=1+1/2*(n-1)=(n+1)/2
an=2/(n+1)
a1=1,an+1=2an/(an+2)(1)求{an}通项公式(2){1/an}为等差数列
a1=1,an+1=2an/(an+2)(1)求{an}通项公式(2){1/an}为等差数列
数学人气:988 ℃时间:2020-06-05 04:36:11
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