x/(x²-x)+2=2x/(x+1)解方程←

　　x/(x²-x)+2=2x/(x+1)
　　[x/x(x-1)]+2=2x/(x+1)
　　1/(x-1)+2=2x/(x+1)
[ 2x/(x+1)]-[1/(x-1)]=2
[ 2x(x-1)/(x+1)(x-1)]-[(x+1)/(x+1)(x-1)]=2
2x^2-2x-x-1=2(x+1(x-1)
2x^2-3x-1=2(x^2-1)
2x^2-3x-1=2x^2-2
3x=1
x=1/3
此题主要考的是平方差公式,及分数的通分