tan(a+4/π)
=tan((a+b)-(b-π/4))
=(tan(a+b)-tan(b-π/4)))/(1+tan(a+b)tan(b-π/4))
=(2/5-1/4)/(1+(2/5)(1/4))
=(3/20)/(1+2/20)
=3/22
tan(a+b)=5/2,tan(b-4/π)=4/1 求tan(a+4/π)的值
tan(a+b)=5/2,tan(b-4/π)=4/1 求tan(a+4/π)的值
数学人气:968 ℃时间:2020-06-12 02:24:36
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