[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)²
=[-3a^5b^2-3a^6b^2]÷9a^4b^4
=-a/3b^2-a^2/3b^2
=-a/3b^2*(a-1)
=-a/3b^2*0
=0好像不对[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² =[-3a^5b^2-27a^6b^2]÷9a^4b^4=-a/3b^2-3a^2/b^2=-a/3b^2*(a-9)b等于什么?b=负二分之一[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² =[9a^5b^2-27a^6b^2]÷9a^4b^4=a/b^2-3a^2/b^2=a/b^2*(1-3a)=1/(-1/2)^2*(1-3)=1/(1/4)*(-2)=4*(-2)=-8
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-
[(-3ab)²×a³+2a³×(-3ab)³×1/2b]÷(3a²b²)² ,其中a=1/3,b=-
b=-(1/2)
b=-(1/2)
数学人气:168 ℃时间:2019-10-11 01:01:29
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