a^2+b^2+4a-8b+20=0
(a^2+4a+4)+(b^2-8b+16)=0
即(a+2)^2+(b-4)^2=0
可得a=-2,b=4
代回为x^2+y^2-4-2axy=(x-y)^2-4=(x-y-2)(x-y+2)
已知a,b满足a^2+b^2+4a-8b+20=0,试分解(x^2+y^2)-(b+axy).
已知a,b满足a^2+b^2+4a-8b+20=0,试分解(x^2+y^2)-(b+axy).
数学人气:640 ℃时间:2020-02-05 01:02:52
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