∴z=
| 5 |
| 2−i |
| 5(2+i) |
| (2−i)(2+i) |
| 5(2+i) |
| 5 |
∴|z|=
| 22+12 |
| 5 |
故选A．
已知复数z满足（2-i）z=5（i为虚数单位）则|z|=（ ） A.5 B.3 C.2 D.1
已知复数z满足（2-i）z=5（i为虚数单位）则|z|=（ ）
A.
B. 3
C. 2
D. 1
A.
| 5 |
B. 3
C. 2
D. 1
数学人气：575 ℃时间：2019-08-21 10:54:22
优质解答
∵复数z满足（2-i）z=5（i是虚数单位），
∴z=
=
=
=2+i．
∴|z|=
=
．
故选A．
∴z=
∴|z|=
故选A．
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