∠AOC=∠BOD
1.当OC在∠AOB外时:
∠AOC=∠AOB+∠BOC=90º+∠BOC=∠COD+∠BOC=∠BOD
2.当OC在∠AOB内时:
∠AOC=∠AOB-∠BOC=90°-∠BOC=∠COD-∠BOC=∠BOD
已知角AOB=角COD=90度,则角AOC与角BOD有怎样的大小关系?为什么?
已知角AOB=角COD=90度,则角AOC与角BOD有怎样的大小关系?为什么?
数学人气:822 ℃时间:2020-05-24 01:10:09
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