若函数f(x)=a2x2(a>0),g(x)=blnx.(1)若函数y=f(x)图像上的点到直线x-y-3=0距离的最小值为根号2,求a的值

f(x)上的点到x-y-3=0的距离＝｜x-a^2x^2-3|/根号2＝｜a^2x^2-x+3|/根号2a^2x^2-x+3=a^2(x-1/2a^2)+3-1/(4a^2)当x=1/(2a^2)时有最小值是3-1/(4a^2)即|3-1/4a^2|/根号2＝根号2｜3-1/4a^2|=23-1/4a^2=2或－21/4a^2=1或5...