已知x平方+x平方=2x+4y求代数式[2x平方-（x+y）(x-y)][(x+y-1)(x-y+1)+1-2y]的值

x²+y²+5=2x+4y
x²-2x+1+y²-4y+4=0
(x-1)² + (y-2)²=0
∵(x-1)²≥0且(y-2)²≥0
∴x=1,y=2
[2x²-(x+y)(x-y)][(x+y-1)(x-y+1)+1-2y]=[2x²-(x²-y²)][x²-(y-1)²+1-2y]=(x²+y²)(x²-y²)=x^4 - y^4
=1^4 - 2^4
=-15