已知函数y= log2(x2-ax+1)有最小值,则a的取值范围是?
已知函数y= log2(x2-ax+1)有最小值,则a的取值范围是?
数学人气:840 ℃时间:2019-10-18 22:41:19
优质解答
如果不考虑X范围,Log2单增,而x2-ax+1恒有极小值所以a应该属于R.考虑X属于R,则需X2-aX+1>0,二次函数特征-2
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