设y=f(secx),f'(x)=x 则dy/dx /x=二分之派

y = f(secx),f '(x) = x
y ' = f ' (secx) * (secx) ' = secx * secx tanx = sec²x tanx
x->π/2,dy/dx -> ∞感谢您回答 答案是2如果f '(x) = x 必有 f(x) = x² /2 + C (C为一个常数)y = f(secx) = sec²x /2 + Cy ' = secx * secx tanx = sec²x tanx 当x=π/4时,dy/dx = 2 。4分之派是什么啊当x->π/2时,dy/dx -> ∞; 当x=π/4时,dy/dx = 2请检查题目。