若函数f（x）=（sinx+cosx）+2cos²x-m在[0,π/2]上有零点,求m的取值范围
若函数f（x）=（sinx+cosx）+2cos²x-m在[0,π/2]上有零点,求m的取值范围
更正：f（x）=（sinx+cosx）²+2cos²x-m在[0，π/2]上有零点，求m的取值范围
更正：f（x）=（sinx+cosx）²+2cos²x-m在[0，π/2]上有零点，求m的取值范围
数学人气：129 ℃时间：2019-08-22 10:44:57
优质解答
题目有误吧,f（x）=（sinx+cosx）²+2cos²x-m在[0,π/2]上有零点即方程 （sinx+cosx）²+2cos²x-m=0在[0,π/2]上有解即求 m=（sinx+cosx）²+2cos²x的值域所以 m=（sinx+cosx）²+2c...
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