f﹙x²﹚的定义域是[-1,1],则
-1≤x≤1
于是
0≤x²≤1
所以f(x)定义域为[0,1]
f(2x+1)的定义域:
0≤2x+1≤1
-1≤2x≤0
-1/2≤x≤0
所以:f(2x+1)的定义域[-1/2,0]
已知函数f﹙x²﹚的定义域是[-1,1],求f﹙2x+1﹚的定义域
已知函数f﹙x²﹚的定义域是[-1,1],求f﹙2x+1﹚的定义域
数学人气:663 ℃时间:2019-08-21 19:16:38
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