化简：sin^6α+cos^6α+3sin^2α*cos^2α=?

数学人气：419 ℃时间：2019-12-24 09:47:19

优质解答

sin^6α+cos^6α+3sin^2α*cos^2α
=(sin^2α+cos^2α)(sin^4α-sin^2α*cos^2α+cos^4α)+3sin^2α*cos^2α
=sin^4α+2sin^2α*cos^2α+cos^4α
=(sin^2α+cos^2α)^2
=1

我来回答

类似推荐

猜你喜欢